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Simplifying b2 + 19bc + 48c2 = 0 Reorder the terms: 19bc + b2 + 48c2 = 0 Solving 19bc + b2 + 48c2 = 0 Solving for variable 'b'. Factor a trinomial. (b + 3c)(b + 16c) = 0Subproblem 1
Set the factor '(b + 3c)' equal to zero and attempt to solve: Simplifying b + 3c = 0 Solving b + 3c = 0 Move all terms containing b to the left, all other terms to the right. Add '-3c' to each side of the equation. b + 3c + -3c = 0 + -3c Combine like terms: 3c + -3c = 0 b + 0 = 0 + -3c b = 0 + -3c Remove the zero: b = -3c Simplifying b = -3cSubproblem 2
Set the factor '(b + 16c)' equal to zero and attempt to solve: Simplifying b + 16c = 0 Solving b + 16c = 0 Move all terms containing b to the left, all other terms to the right. Add '-16c' to each side of the equation. b + 16c + -16c = 0 + -16c Combine like terms: 16c + -16c = 0 b + 0 = 0 + -16c b = 0 + -16c Remove the zero: b = -16c Simplifying b = -16cSolution
b = {-3c, -16c}
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